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number system-addition and subtaction

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我想問直式點計到出黎 1 1010(2)+1110(2) 1010 +1110 ------------- 11000 DE +AB ---------- 189 E(16)+B(16)=19(16) 點樣得出呢個結果? 減數點計?

最佳解答:

In base-10, 123 = (10)^2 * 1 + (10)^1 * 2 + (10)^0 * 3 = 100 + 20 + 3 = 123 In base-16, DE = (16)^1 * 13 + (16)^0 * 14 = 208 + 14 = 222 Similarly, convert base-16 to base-10: E = 14 B = 11 E + B = 25 25 / 16 = 1 with remainder 9 thus = 19 (base-16) Subtraction: Same idea... For example: DE - F E is smaller than F, so you borrow 1 (i.e. 16 because it is base-16) from the left digit D, D - 1 becomes C. Add the 1 to the right digit: (E + 16) - F = 30 - F = 30 - 15 = 15 Attaching left digit C to 15, we have CF

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