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標題:
有冇人識做呢條數?
發問:
In the given multiplication, different letters represent different integers ranging from 0 to 9. Find the value of A + B + C + D ABCD x 9 = DCBA
ABCD x 9 = DCBA If A > 1 , ABCD x 9 is a 5 digits number, so A = 1, If B = 2 or above , 12CD x 9 > 1200 x 9 = 10800 is a 5 digits number, So B = 0. The last digit of D x 9 = A = 1 , so D = 9 or 1(rejected since A = 1) Becomes 10C9 x 9 = 9C01 (1009 + 10*C) x 9 = 9001 + 100*C 9081 + 90*C = 9001 + 100*C 10*C = 80 C = 8 A + B + C + D = 1 + 0 + 8 + 9 = 18
其他解答:
有冇人識做呢條數?
發問:
In the given multiplication, different letters represent different integers ranging from 0 to 9. Find the value of A + B + C + D ABCD x 9 = DCBA
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最佳解答:ABCD x 9 = DCBA If A > 1 , ABCD x 9 is a 5 digits number, so A = 1, If B = 2 or above , 12CD x 9 > 1200 x 9 = 10800 is a 5 digits number, So B = 0. The last digit of D x 9 = A = 1 , so D = 9 or 1(rejected since A = 1) Becomes 10C9 x 9 = 9C01 (1009 + 10*C) x 9 = 9001 + 100*C 9081 + 90*C = 9001 + 100*C 10*C = 80 C = 8 A + B + C + D = 1 + 0 + 8 + 9 = 18
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