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標題:

MATHS Ex12A 6,7,9

發問:

MATHS Ex12A 6,7,9 [IMG]http://i293.photobucket.com/albums/mm67/zaza520/0002-6.jpg[/IMG] [IMG]http://i293.photobucket.com/albums/mm67/zaza520/0003-5.jpg[/IMG] [IMG]http://i293.photobucket.com/albums/mm67/zaza520/0004-3.jpg[/IMG]

最佳解答:

(6a) -2/x + 1 = 0 From the graph, it meets the x-axis at x = 2, so x = 2. (6b) 14/5 - 2/x = 0 9/5 + (-2/x + 1) = 0 -2/x + 1 = -9/5 From the graph, the curve locates y = -9/5 at x = 0.7 (approx.) (7a) Equating the y's together: x2 + 3x - 3 = 2x - 2 x2 + x - 1 = 0 which is the equation to be solved through finding the points of intersection. (7b) Around x = 0.7 and x = -1.7 (9a) Equating the y's together: -9x2 + 8x = 6 - 7x 9x2 - 15x + 6 = 0 (9b) Equating the y's together: 3x3 - x - 1 = x/3 9x3 - 3x - 3 = x 9x3 - 4x - 3 = 0

其他解答:

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