close

標題:

此文章來自奇摩知識+如有不便請留言告知

Mathematies questions(3)

發問:

a 3/1x5-7/5x9+11/13x17+19/17x21-...+2011/2009x2013=?b ABxBC__________ABCD E__________CBBBABDE this number is ?cABCDBCDCD+D_______________2012ABCD this numder is ?d88+1_ _+_ _8=8_ _+_ _1+88THE NUMBER MUST BE... 顯示更多 a 3/1x5-7/5x9+11/13x17+19/17x21-...+2011/2009x2013=? b AB xBC __________ AB CD E __________ CBBBABDE this number is ? c ABCD BCD CD +D _______________ 2012ABCD this numder is ? d88+1_ _+_ _8=8_ _+_ _1+88THE NUMBER MUST BE 1/8/0 e68-6_+_8=8_+_9-89THE NUMBER MUST BE 1/6/8/9/0

最佳解答:

3/1x5 - 7/5x9 + 11/9x13 - 15/13x17 + ... + 2011/2009x2013 = (1/2+1/10) - (1/10+1/18) + (1/18+1/26) - (1/26+1/34) + ... + (1/4018+1/4026) = 1/2 + 1/4026 = 1012/2013 43 x31 ----- 43 129 ----- 1333 1468 468 68 8 ----- 2012 88 + 101 + 808 = 808 + 101 + 88 (many possible solutions) 68 - 68 + 18 = 88 + 19 - 89 (many possible solutions)

其他解答:

c) We start from right hand side first. D = 3 or D = 8. There are 2 possible ways. Let D be 3. Then everything will work out fine. If D is 3, then C must be 0. If C is 0, then B must be 0 too. If B is 0, then A must be 2. Therefore, ABCD is 2003. For the case D = 8. It won't work out at all.|||||(d) has many solutions : 88+101+808 = 808+101+88 88+111+808 = 818+101+88 88+181+808 = 888+101+88 88+111+888 = 888+111+88 ...|||||邊位都好 老師 英明~|||||第一題是否打漏了?應該係 3/1x5-7/5x9+11/9x13-15/13x17+19/17x21-...+2011/2009x2013=?|||||Very difficult *_*5AEEC82B53E1B405

arrow
arrow
    創作者介紹
    創作者 christi56o4 的頭像
    christi56o4

    快遞百科

    christi56o4 發表在 痞客邦 留言(0) 人氣()