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標題:
發問:
How to calculate 1-100 by using 1,9,9,3 this four numbers? I don't care you use +, -, x, /, Square, Pie..... E.G: 9-9x1+3=3, 9-9+1+3=4, 1+9/9+3=5. I need to know how to do 47, 61, 65, 70-73, 88, 89?
最佳解答:
9 × 9 + 32 - 1 = 89 92 + 9 + 1 - 3 = 88 92 - 9 + 1 - 3 = 70 (9 + 9) × (3 + 1) = 72 (9 + 1)2 - 92/3 = 73 (9 - 1)2 - 9/3 = 61 (9 - 1)2 + 9/32 = 65 2008-02-13 11:36:35 補充： 3^3 - 9 十 √9 - 1 = 47 2008-02-13 11:39:29 補充： 9^2 - 1 × (3^3)/9 = 729^2 - 1 - (3^3)/9 = 71 2008-02-13 11:51:03 補充： Sorry for the previous mistake in 47, it should be:arctan (1) 十 3 - 9/9 = 47since arctan (1) = 45
其他解答:
39+9-1 = 47 (9+9)x(3+1) = 72|||||39+9-1 = 47 (9+9)x(3+1) = 72 這樣可不可呢?554581090DCCD3AC
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How to calculate 1-100 by using 1,9,9,3 this four numbers?發問:
How to calculate 1-100 by using 1,9,9,3 this four numbers? I don't care you use +, -, x, /, Square, Pie..... E.G: 9-9x1+3=3, 9-9+1+3=4, 1+9/9+3=5. I need to know how to do 47, 61, 65, 70-73, 88, 89?
最佳解答:
9 × 9 + 32 - 1 = 89 92 + 9 + 1 - 3 = 88 92 - 9 + 1 - 3 = 70 (9 + 9) × (3 + 1) = 72 (9 + 1)2 - 92/3 = 73 (9 - 1)2 - 9/3 = 61 (9 - 1)2 + 9/32 = 65 2008-02-13 11:36:35 補充： 3^3 - 9 十 √9 - 1 = 47 2008-02-13 11:39:29 補充： 9^2 - 1 × (3^3)/9 = 729^2 - 1 - (3^3)/9 = 71 2008-02-13 11:51:03 補充： Sorry for the previous mistake in 47, it should be:arctan (1) 十 3 - 9/9 = 47since arctan (1) = 45
其他解答:
39+9-1 = 47 (9+9)x(3+1) = 72|||||39+9-1 = 47 (9+9)x(3+1) = 72 這樣可不可呢?554581090DCCD3AC
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